{"id":2013,"date":"2023-10-14T11:19:45","date_gmt":"2023-10-14T11:19:45","guid":{"rendered":"https:\/\/www.matematikazavsicki.com\/tr\/?p=2013"},"modified":"2023-10-14T11:19:46","modified_gmt":"2023-10-14T11:19:46","slug":"eskenar-dortgen-kosegenler","status":"publish","type":"post","link":"https:\/\/www.matematikazavsicki.com\/tr\/eskenar-dortgen-kosegenler\/","title":{"rendered":"E\u015fkenar D\u00f6rtgen K\u00f6\u015fegenler"},"content":{"rendered":"\n<p>Bir e\u015fkenar d\u00f6rtgen k\u00f6\u015fegenler, e\u015fkenar d\u00f6rtgenin a\u00e7\u0131lar\u0131n\u0131n ortaortaylar\u0131d\u0131r. A\u00e7\u0131lar\u0131 ikiye b\u00f6lerler ama di\u011fer yandan kar\u015f\u0131l\u0131kl\u0131 olarak birbirlerini ortalarlar. Bunun tam olarak ne anlama geldi\u011fini analiz edelim!<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">E\u015fkenar D\u00f6rtgen K\u00f6\u015fegenler A\u00e7\u0131lar\u0131n Ortaortaylar\u0131d\u0131r<\/h2>\n\n\n\n<p>\u0130ki k\u00f6\u015fegen d\u00f6rt a\u00e7\u0131n\u0131n tamam\u0131n\u0131 ikiye b\u00f6ler. \u00d6n\u00fcn\u00fczde e\u015fkenar d\u00f6rtgendeki a\u00e7\u0131lardan birinin (veya t\u00fcm a\u00e7\u0131lar\u0131n) boyutunu belirlemeniz gereken bir g\u00f6reviniz varsa, bu kural belirli matematik g\u00f6revlerinde \u00e7ok yararl\u0131 olabilir. Herhangi bir e\u015fkenar d\u00f6rtgende z\u0131t a\u00e7\u0131lar\u0131n birbirine e\u015fit oldu\u011funu unutmayal\u0131m.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"500\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Eskenar-Dortgen-kosegenler.jpg\" alt=\"E\u015fkenar D\u00f6rtgen k\u00f6\u015fegenler\" class=\"wp-image-2019\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Eskenar-Dortgen-kosegenler.jpg 500w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Eskenar-Dortgen-kosegenler-300x300.jpg 300w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Eskenar-Dortgen-kosegenler-150x150.jpg 150w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><\/figure>\n<\/div>\n\n\n<h3 class=\"wp-block-heading\">K\u00f6\u015fegenler Birbirini Ortalar<\/h3>\n\n\n\n<p>E\u015fkenar d\u00f6rtgendeki iki k\u00f6\u015fegen ikiye b\u00f6l\u00fcnm\u00fc\u015ft\u00fcr, yani tam orta noktalar\u0131nda kesi\u015firler. Bu herhangi bir e\u015fkenar d\u00f6rtgen i\u00e7in ge\u00e7erlidir. Kesin olarak bu bilgiyle geometrik g\u00f6revlerde \u00e7ok say\u0131da problemin \u00e7\u00f6z\u00fclebilece\u011fi ve bu ger\u00e7e\u011fin etkili bir \u015fekilde kullan\u0131labilece\u011fi a\u00e7\u0131kt\u0131r.<\/p>\n\n\n\n<p>Di\u011fer geometri yasalar\u0131yla, <a href=\"https:\/\/www.matematikazavsicki.com\/tr\/pisagor-teoremi\/\">Pisagor teoremi<\/a> (k\u00f6\u015fegenlerin \u00e7izilmesi e\u015fkenar d\u00f6rtgende d\u00f6rt dik \u00fc\u00e7gen \u00fcretir) ile birle\u015ftirildi\u011finde, k\u00f6\u015fegenlerin orta noktada kesi\u015fti\u011fi ger\u00e7e\u011fi bir\u00e7ok sorunu \u00e7\u00f6zmek i\u00e7in \u00e7ok g\u00fc\u00e7l\u00fc bir silaht\u0131r.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Bir E\u015fkenar D\u00f6rtgenin K\u00f6\u015fegenlerinin Kesi\u015fiminde Bir Tepe Noktas\u0131na Sahip Olan A\u00e7\u0131lar\u0131n Her Biri 90 Derecedir<\/h4>\n\n\n\n<p>Mant\u0131ksal olarak e\u015fkenar d\u00f6rtgenin iki k\u00f6\u015fegeninin kesi\u015fimi d\u00f6rt a\u00e7\u0131 olu\u015fturur. Bu d\u00f6rt farkl\u0131 a\u00e7\u0131n\u0131n birbirine e\u015fit oldu\u011funu ve her birinin tam olarak 90 derece (dik <a href=\"https:\/\/www.matematikazavsicki.com\/tr\/aci-turleri\/\">a\u00e7\u0131<\/a>) oldu\u011funu bilmek \u00f6nemlidir. Bu kesinlikle \u00e7ok yararl\u0131 bir bilgidir \u00e7\u00fcnk\u00fc e\u015fkenar d\u00f6rtgeni d\u00f6rt dik \u00fc\u00e7gene b\u00f6lmemiz bize Pisagor teoreminin uygulanmas\u0131n\u0131n elimizde oldu\u011funu ve bunu bilinmeyen boyuttaki a\u00e7\u0131lar\u0131 veya bilinmeyen uzunluktaki kenarlar\u0131 belirlemek i\u00e7in kullanabilece\u011fimizi s\u00f6yler.<\/p>\n\n\n\n<p>Rom&#8217;daki k\u00f6\u015fegenlerle ilgili bu \u00fc\u00e7 ger\u00e7ek \u00e7ok faydal\u0131d\u0131r ve hi\u00e7 kimse bunlar\u0131 unutmamal\u0131d\u0131r. Belirli bir sorunu \u00e7\u00f6zebilmek i\u00e7in mant\u0131\u011f\u0131 ve daha farkl\u0131 bilgileri kullanmak zorunda oldu\u011funuz bu matematiksel-geometrik g\u00f6revlerde, her zaman &#8220;kutunun d\u0131\u015f\u0131nda&#8221; d\u00fc\u015f\u00fcnmeye \u00e7al\u0131\u015f\u0131n. \u0130yi \u015fanlar!<\/p>\n\n\n\n<hr class=\"wp-block-separator has-css-opacity\"\/>\n\n\n<form role=\"search\" method=\"get\" action=\"https:\/\/www.matematikazavsicki.com\/tr\/\" class=\"wp-block-search__button-outside wp-block-search__icon-button wp-block-search\"    ><label class=\"wp-block-search__label\" for=\"wp-block-search__input-1\" >Gerekli malzemeyi kolayca bulun! 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A\u00e7\u0131lar\u0131 ikiye b\u00f6lerler ama di\u011fer yandan kar\u015f\u0131l\u0131kl\u0131 olarak birbirlerini ortalarlar. Bunun tam olarak ne anlama geldi\u011fini analiz edelim! E\u015fkenar D\u00f6rtgen K\u00f6\u015fegenler A\u00e7\u0131lar\u0131n [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":2019,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2,3,4,8],"tags":[262,79,405],"class_list":["post-2013","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-5-sinif-matematik","category-6-sinif-matematik","category-7-sinif-matematik","category-geometri","tag-dortgen","tag-eskenar","tag-kosegenler"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>E\u015fkenar D\u00f6rtgen K\u00f6\u015fegenler<\/title>\n<meta name=\"description\" content=\"Bir e\u015fkenar d\u00f6rtgen k\u00f6\u015fegenler, e\u015fkenar d\u00f6rtgenin a\u00e7\u0131lar\u0131n\u0131n ortaortaylar\u0131d\u0131r. 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