{"id":1710,"date":"2023-10-02T23:18:33","date_gmt":"2023-10-02T23:18:33","guid":{"rendered":"https:\/\/www.matematikazavsicki.com\/tr\/?p=1710"},"modified":"2023-10-02T23:18:34","modified_gmt":"2023-10-02T23:18:34","slug":"birlesik-devrede-toplam-direnc","status":"publish","type":"post","link":"https:\/\/www.matematikazavsicki.com\/tr\/birlesik-devrede-toplam-direnc\/","title":{"rendered":"Birle\u015fik Devrede Toplam Diren\u00e7"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Kombine bir devredeki toplam elektrik direncini hesaplamak i\u00e7in, toplam elektrik direncini hesaplamaya y\u00f6nelik form\u00fclleri ayr\u0131 ayr\u0131 bilmek gerekir:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Seri devre<\/li>\n\n\n\n<li>Paralel ak\u0131m devresi<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Seri ve paralel ak\u0131m devresinde toplam elektrik direncini hesaplamak i\u00e7in form\u00fcller uygulanarak, yaln\u0131zca toplam direnci belirlenen ak\u0131m devresi i\u00e7in ge\u00e7erli olan yeni bir birle\u015fik ak\u0131m devresi form\u00fcl\u00fc olu\u015fturulur. Bu nedenle birle\u015fik devrelerde e\u015fde\u011fer direncin belirlenmesi daha karma\u015f\u0131kt\u0131r. A\u015fa\u011f\u0131da g\u00f6rebilece\u011finiz \u00f6rnekler (metin ve video format\u0131nda), yeni form\u00fcllerin (seri ve paralel devrelere dayal\u0131 olarak) nas\u0131l olu\u015fturuldu\u011funu anlaman\u0131za yard\u0131mc\u0131 olacakt\u0131r.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Kombine Devrede Elektrik Direncinin Hesaplanmas\u0131<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">T\u00fcketiciler (diren\u00e7ler) aras\u0131nda hem seri hem de paralel ba\u011flant\u0131 i\u00e7eren bir devreye birle\u015fik devre denir. Seri ve paralel ba\u011flant\u0131n\u0131n birle\u015fimi nedeniyle, toplam diren\u00e7 hesaplan\u0131rken her iki ba\u011flant\u0131 y\u00f6ntemi i\u00e7in ayr\u0131 form\u00fcller kullan\u0131lmal\u0131d\u0131r.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0130lk \u00f6nce ka\u00e7 farkl\u0131 \u00fcyenin seri olarak ba\u011fland\u0131\u011f\u0131n\u0131 bulmak en iyisidir. Birle\u015fik devredeki toplam direnci, <a href=\"https:\/\/www.matematikazavsicki.com\/tr\/elektriksel-direnc\/\">seri ba\u011fl\u0131 bireysel par\u00e7alar\u0131n toplam\u0131<\/a> olarak temsil ederiz.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Elbette \u00e7ok dikkatli olmak gerekiyor \u00e7\u00fcnk\u00fc di\u011ferlerine seri ba\u011flanan bir \u00fcyenin kendisi de iki, \u00fc\u00e7 veya daha fazla \u00fcyenin paralel ba\u011flant\u0131s\u0131 olabilir. Bu durumda, \u00f6nce o eleman\u0131n direnci hesaplan\u0131r (<a href=\"https:\/\/www.matematikazavsicki.com\/tr\/paralel-bagli-direncler\/\">paralel ak\u0131m devrelerindeki toplam diren\u00e7 form\u00fcl\u00fc<\/a> kullan\u0131larak) ve ancak daha sonra bu de\u011ferle birle\u015fik ak\u0131m devresindeki toplam direncin hesaplanmas\u0131na yakla\u015f\u0131l\u0131r.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u00c7\u00f6z\u00fclmesi en karma\u015f\u0131k olan\u0131, hem seri hem de paralel ba\u011flant\u0131 i\u00e7eren bir eleman\u0131 olan devrelerdir.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A\u015fa\u011f\u0131daki \u00e7\u00f6z\u00fclm\u00fc\u015f \u00f6rne\u011fe bak\u0131n. Bu \u00f6rnek, \u00fc\u00e7 t\u00fcketiciye (diren\u00e7lere) sahip en basit birle\u015fik devreyi i\u00e7ermektedir.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Kombine Devrede Toplam Direncin Hesaplanmas\u0131na Bir \u00d6rnek<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">\u00d6rnek 1: A\u015fa\u011f\u0131daki \u015fekilde verilen birle\u015fik devredeki toplam (e\u015fde\u011fer) elektrik direncini hesaplay\u0131n:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Uc-tuketicili-birlesik-devre.jpg\" alt=\"\u00dc\u00e7 t\u00fcketicili birle\u015fik devre\" class=\"wp-image-1723\" style=\"width:568px;height:350px\" width=\"568\" height=\"350\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Uc-tuketicili-birlesik-devre.jpg 867w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Uc-tuketicili-birlesik-devre-300x185.jpg 300w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Uc-tuketicili-birlesik-devre-768x474.jpg 768w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Uc-tuketicili-birlesik-devre-624x385.jpg 624w\" sizes=\"auto, (max-width: 568px) 100vw, 568px\" \/><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Yukar\u0131daki resimde birbirine ba\u011fl\u0131 \u00fc\u00e7 t\u00fcketici bulunmaktad\u0131r. Ak\u0131m devresinin seri ba\u011fl\u0131 iki farkl\u0131 par\u00e7a i\u00e7erdi\u011fi resimden a\u00e7\u0131k\u00e7a g\u00f6r\u00fclmektedir! Bu kadar:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Elektrik direnci R olan ilk t\u00fcketici.<\/li>\n\n\n\n<li>S\u0131ras\u0131yla R iki ve R \u00fc\u00e7 elektrik direncine sahip ikinci ve \u00fc\u00e7\u00fcnc\u00fc t\u00fcketiciler aras\u0131ndaki paralel ba\u011flant\u0131.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Bu durumda seri ba\u011fl\u0131 yaln\u0131zca iki eleman oldu\u011fundan, birle\u015fik devredeki toplam diren\u00e7 i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc olu\u015ftururuz:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"283\" height=\"88\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kombine-devrede-toplam-elektrik-direncini-hesaplamak-icin-formul.jpg\" alt=\"Kombine devrede toplam elektrik direncini hesaplamak i\u00e7in form\u00fcl\" class=\"wp-image-1725\"\/><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Mant\u0131ksal olarak, \u00f6nce paralel ba\u011flant\u0131 R&#8217;deki (bir-iki) toplam elektrik direncini belirleyece\u011fiz, ard\u0131ndan bu de\u011ferle t\u00fcm birle\u015fik devrenin toplam elektrik direncini belirlemek i\u00e7in orijinal form\u00fcle geri d\u00f6nece\u011fiz!<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Paralel ba\u011flant\u0131 i\u00e7in, belirli paralel daldaki t\u00fcketici say\u0131s\u0131na g\u00f6re ayarlanm\u0131\u015f kar\u015f\u0131l\u0131kl\u0131 de\u011ferlere sahip form\u00fcl\u00fc kullan\u0131r\u0131z. \u015e\u00f6yle yaz\u0131yor:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"273\" height=\"137\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Paralel-baglantida-elektriksel-direnc.jpg\" alt=\"Paralel ba\u011flant\u0131da elektriksel diren\u00e7\" class=\"wp-image-1727\"\/><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">\u0130kinci ve \u00fc\u00e7\u00fcnc\u00fc t\u00fcketicinin de\u011ferlerinin de\u011fi\u015ftirilmesiyle ifade elde edilir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"238\" height=\"136\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Ikinci-ve-ucuncu-musteriler-icin-degerlerin-degistirilmesi.jpg\" alt=\"\u0130kinci ve \u00fc\u00e7\u00fcnc\u00fc m\u00fc\u015fteriler i\u00e7in de\u011ferlerin de\u011fi\u015ftirilmesi\" class=\"wp-image-1729\"\/><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\"><a href=\"https:\/\/www.matematikazavsicki.com\/tr\/en-kucuk-ortak-kat\/\">En k\u00fc\u00e7\u00fck ortak kat<\/a> 3 ve 6 say\u0131lar\u0131yla de\u011fi\u015ftirip kesirleri payda 6&#8217;ya geni\u015flettikten sonra \u015funu elde ederiz:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"232\" height=\"125\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Ayni-paydalara-genisleme.jpg\" alt=\"Ayn\u0131 paydalara geni\u015fleme\" class=\"wp-image-1731\"\/><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Buradan ayn\u0131 paydalara sahip kesirleri toplad\u0131\u011f\u0131m\u0131zda son ad\u0131ma ula\u015f\u0131yoruz:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"169\" height=\"132\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Paralel-baglantida-bireysel-karsilikli-degerlerin-eklenmesi.jpg\" alt=\"Paralel ba\u011flant\u0131da bireysel kar\u015f\u0131l\u0131kl\u0131 de\u011ferlerin eklenmesi\" class=\"wp-image-1733\"\/><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Son olarak, uygun d\u00f6nd\u00fcrmeyle (e\u015fittir i\u015faretinin soluna ve sa\u011f\u0131na) \u015funu elde ederiz:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"261\" height=\"121\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Birlesik-devrenin-paralel-kismindaki-toplam-elektrik-direnci.jpg\" alt=\"Birle\u015fik devrenin paralel k\u0131sm\u0131ndaki toplam elektrik direnci\" class=\"wp-image-1735\"\/><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">\u0130kinci ve \u00fc\u00e7\u00fcnc\u00fc t\u00fcketiciler aras\u0131ndaki paralel ba\u011flant\u0131n\u0131n toplam direnci 2 ohm&#8217;dur.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Son olarak, ilk form\u00fclde \u00f6nceden elde edilen de\u011feri de\u011fi\u015ftirmeye devam ediyor, bu da bize \u015funu veriyor:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"435\" height=\"77\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kombine-devredeki-toplam-elektrik-direncinin-degeri.jpg\" alt=\"Kombine devredeki toplam elektrik direncinin de\u011feri\" class=\"wp-image-1737\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kombine-devredeki-toplam-elektrik-direncinin-degeri.jpg 435w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kombine-devredeki-toplam-elektrik-direncinin-degeri-300x53.jpg 300w\" sizes=\"auto, (max-width: 435px) 100vw, 435px\" \/><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">T\u00fcm birle\u015fik devrenin toplam elektrik direnci 4 ohm&#8217;dur!<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Video \u00d6rnekleri<\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">A\u015fa\u011f\u0131daki video materyali, her direncin konumunun ayr\u0131 ayr\u0131 birle\u015ftirilmesiyle elde edilen \u00fc\u00e7 farkl\u0131 birle\u015fik devreyi i\u00e7ermektedir. \u0130\u00e7inde a\u015fa\u011f\u0131daki kombinasyonlar\u0131 g\u00f6receksiniz:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Birinci t\u00fcketici, ikinci ve \u00fc\u00e7\u00fcnc\u00fcn\u00fcn paralel ba\u011flant\u0131s\u0131yla seri ba\u011flant\u0131 halindedir.<\/li>\n\n\n\n<li>\u0130kinci t\u00fcketici, birinci ve ikincinin paralel ba\u011flant\u0131s\u0131yla seri ba\u011flant\u0131 halindedir.<\/li>\n\n\n\n<li>\u00dc\u00e7\u00fcnc\u00fc t\u00fcketici, birinci ve ikincinin paralel ba\u011flant\u0131s\u0131yla seri ba\u011flant\u0131 halindedir.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><a href=\"https:\/\/youtu.be\/_-4w1yUOI0s\"><img loading=\"lazy\" decoding=\"async\" width=\"526\" height=\"315\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Birlesik-Devrede-Toplam-Direnc.jpg\" alt=\"Birle\u015fik Devrede Toplam Diren\u00e7\" class=\"wp-image-1739\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Birlesik-Devrede-Toplam-Direnc.jpg 526w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Birlesik-Devrede-Toplam-Direnc-300x180.jpg 300w\" sizes=\"auto, (max-width: 526px) 100vw, 526px\" \/><\/a><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Her farkl\u0131 kombine ak\u0131m devresi, iyi analiz edilmesi, farkl\u0131 par\u00e7alar aras\u0131ndaki ba\u011flant\u0131 \u015feklinin anla\u015f\u0131lmas\u0131 ve ancak o zaman sadece o kombine ak\u0131m devresine uygulanacak yeni bir form\u00fcl olu\u015fturulmas\u0131 gereken yeni bir durumdur!<\/p>\n\n\n\n<hr class=\"wp-block-separator has-css-opacity\"\/>\n\n\n<form role=\"search\" method=\"get\" action=\"https:\/\/www.matematikazavsicki.com\/tr\/\" class=\"wp-block-search__button-outside wp-block-search__icon-button wp-block-search\"    ><label class=\"wp-block-search__label\" for=\"wp-block-search__input-1\" >Gerekli 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[&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":1739,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[132,133,5,6,14],"tags":[393,394,387,260,315,395],"class_list":["post-1710","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-10-sinif-matematik","category-11-sinif-matematik","category-8-sinif-matematik","category-9-sinif-matematik","category-fizik","tag-birlesik","tag-devrede","tag-direnc","tag-formulu","tag-ornek","tag-toplam"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Birle\u015fik Devrede Toplam Diren\u00e7<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.matematikazavsicki.com\/tr\/birlesik-devrede-toplam-direnc\/\" \/>\n<meta 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