{"id":1480,"date":"2023-10-02T15:22:36","date_gmt":"2023-10-02T15:22:36","guid":{"rendered":"https:\/\/www.matematikazavsicki.com\/tr\/?p=1480"},"modified":"2023-10-02T15:22:37","modified_gmt":"2023-10-02T15:22:37","slug":"2ye-3e-veya-6ya-bolunebilme-isaretleri","status":"publish","type":"post","link":"https:\/\/www.matematikazavsicki.com\/tr\/2ye-3e-veya-6ya-bolunebilme-isaretleri\/","title":{"rendered":"2&#8217;Ye 3&#8217;E Veya 6&#8217;Ya B\u00f6l\u00fcnebilme I\u015faretleri"},"content":{"rendered":"\n<p>Burada 2, 3 veya 6&#8217;ya b\u00f6l\u00fcnebilme i\u015faretlerinin \u00f6rneklerini g\u00f6rebilirsiniz! Her i\u015faret i\u00e7in, onu nas\u0131l kullanabilece\u011finizi belirli bir \u00e7\u00f6z\u00fcml\u00fc \u00f6rnekte belirttiniz.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">2 I\u015faretine B\u00f6l\u00fcnebilme<\/h2>\n\n\n\n<p>2&#8217;ye b\u00f6l\u00fcnebilme i\u015fareti \u015fu \u015fekildedir:<\/p>\n\n\n\n<p>Her \u00e7ift tam say\u0131 2&#8217;ye (0, 2, 4, 6 veya 8 rakamlar\u0131ndan biriyle biten bir say\u0131) b\u00f6l\u00fcnebilir. Belirli bir say\u0131 tek ise (1, 3, 5, 7 veya 9 rakamlar\u0131ndan biriyle biten bir say\u0131) 2&#8217;ye b\u00f6l\u00fcnemez.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"352\" height=\"351\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/2-Isaretine-Bolunebilme.jpg\" alt=\"2 I\u015faretine B\u00f6l\u00fcnebilme\" class=\"wp-image-1488\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/2-Isaretine-Bolunebilme.jpg 352w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/2-Isaretine-Bolunebilme-300x300.jpg 300w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/2-Isaretine-Bolunebilme-150x150.jpg 150w\" sizes=\"auto, (max-width: 352px) 100vw, 352px\" \/><\/figure>\n<\/div>\n\n\n<p class=\"has-vivid-purple-color has-text-color\">\u00d6rnek 1: 17, 22, 84 say\u0131lar\u0131ndan hangisi 2&#8217;ye b\u00f6l\u00fcn\u00fcr?<\/p>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">17 say\u0131s\u0131 tek say\u0131 oldu\u011fundan 2&#8217;ye b\u00f6l\u00fcnemez. 22 ve 84 say\u0131lar\u0131 \u00e7ift oldu\u011fundan 2&#8217;ye b\u00f6l\u00fcn\u00fcr.<\/p>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">2&#8217;ye b\u00f6l\u00fcnebilme i\u015fareti genel olarak t\u00fcm b\u00f6l\u00fcnebilme i\u015faretlerinin en basitidir!<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">3&#8217;e B\u00f6l\u00fcnebilme I\u015fareti<\/h2>\n\n\n\n<p>3&#8217;e b\u00f6l\u00fcnebilme i\u015fareti \u015fu \u015fekildedir:<\/p>\n\n\n\n<p>Bir say\u0131n\u0131n rakamlar\u0131n\u0131n toplam\u0131 3&#8217;e b\u00f6l\u00fcn\u00fcyorsa bu say\u0131 3&#8217;e b\u00f6l\u00fcn\u00fcr!<\/p>\n\n\n\n<p>Belirli bir say\u0131n\u0131n 3&#8217;e b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini belirlemek i\u00e7in rakamlar\u0131n\u0131n toplam\u0131n\u0131 bulmam\u0131z gerekir. Bu toplam 3&#8217;e b\u00f6l\u00fcn\u00fcyorsa bu say\u0131 3&#8217;e de b\u00f6l\u00fcn\u00fcyor demektir. Toplam 3&#8217;e b\u00f6l\u00fcnemiyorsa say\u0131 3&#8217;e de b\u00f6l\u00fcnemez.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"350\" height=\"398\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/3e-Bolunebilme-Isareti.jpg\" alt=\"3'e B\u00f6l\u00fcnebilme I\u015fareti\" class=\"wp-image-1490\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/3e-Bolunebilme-Isareti.jpg 350w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/3e-Bolunebilme-Isareti-264x300.jpg 264w\" sizes=\"auto, (max-width: 350px) 100vw, 350px\" \/><\/figure>\n<\/div>\n\n\n<p class=\"has-vivid-red-color has-text-color\">\u00d6rnek 2: 3&#8217;e b\u00f6l\u00fcnebilme i\u015faretini kullanarak 1854 say\u0131s\u0131n\u0131n 3&#8217;e b\u00f6l\u00fcnebilir olup olmad\u0131\u011f\u0131n\u0131 belirleyin!<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">\u00d6ncelikle 1854 say\u0131s\u0131n\u0131n rakamlar\u0131n\u0131n toplam\u0131n\u0131 hesapl\u0131yoruz!<\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-red-color has-text-color has-large-font-size\">1 + 8 + 5 + 4 = 18<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">1854 say\u0131s\u0131n\u0131n rakamlar\u0131n\u0131n toplam\u0131 18&#8217;dir! Rakamlar\u0131n toplam\u0131 3&#8217;e b\u00f6l\u00fcnebildi\u011finden 1854 say\u0131s\u0131n\u0131n 3&#8217;e b\u00f6l\u00fcnebildi\u011fi sonucuna var\u0131r\u0131z. Bunu kan\u0131tlamaya \u00e7al\u0131\u015f\u0131rsak, bunun ge\u00e7erli oldu\u011funu anlar\u0131z:<\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-red-color has-text-color has-large-font-size\">1854 : 3 = 618<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">Bu da 1854 say\u0131s\u0131n\u0131n ger\u00e7ekten de 3 say\u0131s\u0131na b\u00f6l\u00fcnebilece\u011fini do\u011fruluyor.<\/p>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">\u00d6rnek 3: 3&#8217;e b\u00f6l\u00fcnebilme i\u015faretini kullanarak 7631 say\u0131s\u0131n\u0131n 3&#8217;e b\u00f6l\u00fcnebilir olup olmad\u0131\u011f\u0131n\u0131 belirleyin!<\/p>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">\u00d6ncelikle 7631 say\u0131s\u0131n\u0131n rakamlar\u0131n\u0131n toplam\u0131n\u0131 hesapl\u0131yoruz!<\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-purple-color has-text-color has-large-font-size\">7 + 6 + 3 + 1 = 17<\/p>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">7631 say\u0131s\u0131n\u0131n rakamlar\u0131n\u0131n toplam\u0131 17&#8217;dir! Rakamlar\u0131n toplam\u0131 3&#8217;e b\u00f6l\u00fcnemedi\u011finden 7631 say\u0131s\u0131n\u0131n 3&#8217;e b\u00f6l\u00fcnemedi\u011fi sonucuna var\u0131r\u0131z.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">6&#8217;ya B\u00f6l\u00fcnebilme I\u015fareti<\/h2>\n\n\n\n<p>6&#8217;ya b\u00f6l\u00fcnebilme i\u015fareti \u015fu \u015fekildedir:<\/p>\n\n\n\n<p>Belirli bir say\u0131, e\u011fer bu say\u0131 hem 2 hem de 6 say\u0131s\u0131na b\u00f6l\u00fcnebiliyorsa, 6 say\u0131s\u0131na b\u00f6l\u00fcnebilir!<\/p>\n\n\n\n<p>Belirli bir say\u0131n\u0131n 6 say\u0131s\u0131na b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini belirlemek i\u00e7in, bu say\u0131n\u0131n 2&#8217;ye b\u00f6l\u00fcnebilir olup olmad\u0131\u011f\u0131n\u0131 ve 3 say\u0131s\u0131na b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini ayr\u0131 ayr\u0131 belirlememiz gerekir. Verilen say\u0131 her iki say\u0131ya da b\u00f6l\u00fcnebiliyorsa (hem 2&#8217;ye hem de 2&#8217;ye b\u00f6l\u00fcnebilir) 3), bu say\u0131n\u0131n kesinlikle 6&#8217;ya b\u00f6l\u00fcnebildi\u011fi sonucunu \u00e7\u0131kar\u0131yoruz. E\u011fer bir say\u0131 2 veya 3 say\u0131lar\u0131ndan birine b\u00f6l\u00fcnemiyorsa veya 2 veya 3&#8217;e b\u00f6l\u00fcnemiyorsa o say\u0131 kesinlikle b\u00f6l\u00fcnemez 6 numaraya g\u00f6re.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"250\" height=\"280\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/6ya-Bolunebilme-Isareti.jpg\" alt=\"6'ya B\u00f6l\u00fcnebilme I\u015fareti\" class=\"wp-image-1492\"\/><\/figure>\n<\/div>\n\n\n<p class=\"has-vivid-red-color has-text-color\">\u00d6rnek 4: 6&#8217;ya b\u00f6l\u00fcnebilme i\u015faretini kullanarak 9822 say\u0131s\u0131n\u0131n 6&#8217;ya b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini belirleyin!<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">Birinci k\u0131s\u0131m: \u00d6ncelikle 9822 say\u0131s\u0131n\u0131n 2 say\u0131s\u0131na b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini ele al\u0131yoruz.<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">9822 say\u0131s\u0131 2&#8217;ye b\u00f6l\u00fcnebilir \u00e7\u00fcnk\u00fc 9822 say\u0131s\u0131 \u00e7ift say\u0131d\u0131r!<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">3&#8217;e b\u00f6l\u00fcnebilme incelememize devam ediyoruz!<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">\u0130kinci b\u00f6l\u00fcm: 9822 say\u0131s\u0131n\u0131n 3 say\u0131s\u0131na b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini inceliyoruz.<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">\u00d6ncelikle 9822 say\u0131s\u0131n\u0131n rakamlar\u0131n\u0131n toplam\u0131n\u0131 belirliyoruz!<\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-red-color has-text-color has-large-font-size\">9 + 8 + 2 + 2 = 21<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">9822 say\u0131s\u0131n\u0131n rakamlar\u0131n\u0131n toplam\u0131 21&#8217;dir. 21 say\u0131s\u0131 3&#8217;e b\u00f6l\u00fcnebilir, dolay\u0131s\u0131yla 9822 say\u0131s\u0131n\u0131n kesinlikle 3&#8217;e b\u00f6l\u00fcnebilece\u011fi sonucunu \u00e7\u0131kar\u0131yoruz.<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">6&#8217;ya b\u00f6l\u00fcnebilme ile ilgili sonu\u00e7! 9822 say\u0131s\u0131 2&#8217;ye (birinci k\u0131s\u0131m) ve 3&#8217;e (ikinci k\u0131s\u0131m) b\u00f6l\u00fcnebilir, dolay\u0131s\u0131yla hem 2&#8217;ye hem de 3&#8217;e b\u00f6l\u00fcnebildi\u011fi i\u00e7in 9822 say\u0131s\u0131 kesinlikle 6&#8217;ya b\u00f6l\u00fcnebilir!<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">B\u00f6l\u00fcme g\u00f6re kontrol edersek \u015funu elde ederiz:<\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-red-color has-text-color has-large-font-size\">9822 : 6 = 1637<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">Bu da 9822 say\u0131s\u0131n\u0131n ger\u00e7ekten 6 say\u0131s\u0131na b\u00f6l\u00fcnebilece\u011fini do\u011fruluyor.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">6&#8217;ya B\u00f6l\u00fcnemeyen Say\u0131lara \u00d6rnekler<\/h4>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">\u00d6rnek 5: 7941 say\u0131s\u0131n\u0131n 6 say\u0131s\u0131na b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini belirleyin!<\/p>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">7941 say\u0131s\u0131 tektir, bu y\u00fczden 2&#8217;ye b\u00f6l\u00fcnmez. 2 say\u0131s\u0131na b\u00f6l\u00fcnme \u015fart\u0131 sa\u011flanmad\u0131\u011f\u0131 takdirde 7941 say\u0131s\u0131 kesinlikle 6 say\u0131s\u0131na b\u00f6l\u00fcnemez. Bu durumda ihtiyac\u0131m\u0131z yok. 3&#8217;e b\u00f6l\u00fcnebilme incelemesine devam edin.<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">\u00d6rnek 6: 812 say\u0131s\u0131n\u0131n 6 say\u0131s\u0131na b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini belirleyin!<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">Birinci k\u0131s\u0131m: \u00d6ncelikle 812 say\u0131s\u0131n\u0131n 2 say\u0131s\u0131na b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini ele al\u0131yoruz.<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">812 say\u0131s\u0131 2&#8217;ye b\u00f6l\u00fcnebilir \u00e7\u00fcnk\u00fc 812 say\u0131s\u0131 \u00e7ift say\u0131d\u0131r!<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">3&#8217;e b\u00f6l\u00fcnebilme incelememize devam ediyoruz!<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">\u0130kinci b\u00f6l\u00fcm: 812 say\u0131s\u0131n\u0131n 3 say\u0131s\u0131na b\u00f6l\u00fcn\u00fcp b\u00f6l\u00fcnemeyece\u011fini inceliyoruz.<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">\u00d6ncelikle 812 say\u0131s\u0131n\u0131n rakamlar\u0131n\u0131n toplam\u0131n\u0131 belirliyoruz!<\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-red-color has-text-color has-large-font-size\">8 + 1 + 2 = 11<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">812 say\u0131s\u0131n\u0131n rakamlar\u0131n\u0131n toplam\u0131 11&#8217;dir. 11 say\u0131s\u0131 3&#8217;e b\u00f6l\u00fcnmez, dolay\u0131s\u0131yla 9822 say\u0131s\u0131n\u0131n kesinlikle 3&#8217;e b\u00f6l\u00fcnmedi\u011fi sonucuna var\u0131r\u0131z. Son olarak, 812 say\u0131s\u0131n\u0131n 3&#8217;e b\u00f6l\u00fcnemedi\u011fi sonucu \u00e7\u0131kar. 6 say\u0131s\u0131, \u00e7\u00fcnk\u00fc daha \u00f6nce 2 say\u0131s\u0131na b\u00f6l\u00fcnebildi\u011fini tespit etmemize ra\u011fmen 3&#8217;e b\u00f6l\u00fcnemez!<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">Sonu\u00e7 olarak 2&#8217;ye, 3&#8217;e veya 6&#8217;ya b\u00f6l\u00fcnebilme i\u015faretleri birbirleriyle ili\u015fkilidir!<\/p>\n\n\n\n<hr class=\"wp-block-separator has-css-opacity\"\/>\n\n\n<form role=\"search\" method=\"get\" action=\"https:\/\/www.matematikazavsicki.com\/tr\/\" class=\"wp-block-search__button-outside wp-block-search__icon-button wp-block-search\"    ><label class=\"wp-block-search__label\" for=\"wp-block-search__input-1\" >Gerekli malzemeyi kolayca bulun! 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Her i\u015faret i\u00e7in, onu nas\u0131l kullanabilece\u011finizi belirli bir \u00e7\u00f6z\u00fcml\u00fc \u00f6rnekte belirttiniz. 2 I\u015faretine B\u00f6l\u00fcnebilme 2&#8217;ye b\u00f6l\u00fcnebilme i\u015fareti \u015fu \u015fekildedir: Her \u00e7ift [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":1492,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2,3,7],"tags":[370,371,372,373,374,315],"class_list":["post-1480","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-5-sinif-matematik","category-6-sinif-matematik","category-cebir","tag-2ye","tag-3e","tag-6ya","tag-bolunebilme","tag-isaretleri","tag-ornek"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>2&#039;Ye 3&#039;E Veya 6&#039;Ya B\u00f6l\u00fcnebilme I\u015faretleri<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.matematikazavsicki.com\/tr\/2ye-3e-veya-6ya-bolunebilme-isaretleri\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"2&#039;Ye 3&#039;E Veya 6&#039;Ya B\u00f6l\u00fcnebilme I\u015faretleri\" \/>\n<meta property=\"og:description\" content=\"Burada 2, 3 veya 6&#8217;ya b\u00f6l\u00fcnebilme i\u015faretlerinin \u00f6rneklerini g\u00f6rebilirsiniz! 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