{"id":1117,"date":"2023-10-01T22:29:21","date_gmt":"2023-10-01T22:29:21","guid":{"rendered":"https:\/\/www.matematikazavsicki.com\/tr\/?p=1117"},"modified":"2023-10-01T22:29:22","modified_gmt":"2023-10-01T22:29:22","slug":"kaldirac","status":"publish","type":"post","link":"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/","title":{"rendered":"Kald\u0131ra\u00e7"},"content":{"rendered":"\n<p>Kald\u0131ra\u00e7, z\u0131t d\u00f6n\u00fc\u015flere neden olan en az iki kuvvetin etkisi alt\u0131nda, bir nokta veya eksen etraf\u0131nda d\u00f6nebilen herhangi bir kat\u0131 cisimdir. Kald\u0131ra\u00e7, daha b\u00fcy\u00fck bir direncin \u00fcstesinden gelebilece\u011fimiz bir kuvveti uygun \u015fekilde uygulamak i\u00e7in kullan\u0131lan basit bir makinedir.<\/p>\n\n\n\n<p><a href=\"https:\/\/www.matematikazavsicki.com\/tr\/category\/fizik\/\">Fizik<\/a> \u00f6\u011frenmeye yeni ba\u015flayan herkes i\u00e7in basit makineler, bilimin i\u015fimizi ne kadar kolayla\u015ft\u0131rd\u0131\u011f\u0131n\u0131 do\u011frulayan ilk ciddi pratik and\u0131r!<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"274\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kaldirac.jpg\" alt=\"Kald\u0131ra\u00e7\" class=\"wp-image-1126\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kaldirac.jpg 500w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kaldirac-300x164.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><figcaption class=\"wp-element-caption\">\u00c7ift tarafl\u0131 kald\u0131ra\u00e7 \u00f6rne\u011fi<\/figcaption><\/figure>\n<\/div>\n\n\n<h3 class=\"wp-block-heading\">Kald\u0131ra\u00e7 T\u00fcrleri<\/h3>\n\n\n\n<p>Kald\u0131ra\u00e7lar iki kritere g\u00f6re ayr\u0131l\u0131r:<\/p>\n\n\n\n<p>a) Destek noktas\u0131 veya eksenin yerle\u015fimine g\u00f6re:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tek tarafl\u0131 &#8211; dayanak noktas\u0131n\u0131n veya eksenin u\u00e7lar\u0131ndan birinde bulunmad\u0131\u011f\u0131 bir kol.<\/li>\n\n\n\n<li>\u0130ki tarafl\u0131 &#8211; dayanak noktas\u0131n\u0131n veya eksenin iki u\u00e7 noktas\u0131 aras\u0131nda bulundu\u011fu bir kol.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"339\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Tek-Tarafli-Kol.jpg\" alt=\"Tek Tarafl\u0131 Kol\" class=\"wp-image-1129\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Tek-Tarafli-Kol.jpg 500w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Tek-Tarafli-Kol-300x203.jpg 300w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Tek-Tarafli-Kol-84x56.jpg 84w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><figcaption class=\"wp-element-caption\">Kap\u0131 kolu tek tarafl\u0131 bir koldur<\/figcaption><\/figure>\n<\/div>\n\n\n<p>b) Kollar\u0131n uzunlu\u011funa g\u00f6re (\u00e7ift kollar i\u00e7in ge\u00e7erlidir):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u0130kizkenar (ikizkenar) &#8211; kollar\u0131 e\u015fit uzunlukta olan bir kald\u0131ra\u00e7.<\/li>\n\n\n\n<li>\u00c7ok y\u00f6nl\u00fc &#8211; kollar\u0131 farkl\u0131 uzunluklarda olan bir kald\u0131ra\u00e7.<\/li>\n<\/ul>\n\n\n\n<h2 class=\"wp-block-heading\">Kol Denge Ko\u015fulu<\/h2>\n\n\n\n<p>Diyelim ki elimizde iki tarafl\u0131 bir kald\u0131ra\u00e7 var. Kollar\u0131ndan birine bir y\u00fck bindi\u011fini ve kar\u015f\u0131 tarafa belli bir kuvvetle etki etti\u011fimizi d\u00fc\u015f\u00fcnelim. Bu durumda y\u00fck\u00fcn destek noktas\u0131na olan mesafesine y\u00fck\u00fcn aya\u011f\u0131 denir ve b ile g\u00f6sterilir, kuvvetin etki etti\u011fi yerden destek noktas\u0131na olan mesafeye ise kuvvet aya\u011f\u0131 denir ve ile g\u00f6sterilir. A. Kuvvet F ile, y\u00fck ise G ile g\u00f6sterilir.<\/p>\n\n\n\n<p>Kald\u0131ra\u00e7 denge ko\u015fulu \u015f\u00f6yle okunur:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kol-denge-kosulu.jpg\" alt=\"Kol denge ko\u015fulu\" class=\"wp-image-1132\" style=\"width:205px;height:52px\" width=\"205\" height=\"52\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kol-denge-kosulu.jpg 327w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kol-denge-kosulu-300x76.jpg 300w\" sizes=\"auto, (max-width: 205px) 100vw, 205px\" \/><\/figure>\n<\/div>\n\n\n<p>F \u00e7arp\u0131 a \u00e7arp\u0131m\u0131na kuvvet momenti, G \u00e7arp\u0131 b \u00e7arp\u0131m\u0131na ise y\u00fck\u00fcn momenti denir. Kald\u0131ra\u00e7 denge ko\u015fulu bazen moment dengesi olarak da kabul edilir.<\/p>\n\n\n\n<p>Buradan hareketle sadece kuvvetin b\u00fcy\u00fckl\u00fc\u011f\u00fcn\u00fc ifade etmek istersek d\u00f6n\u00fc\u015f\u00fcm sonras\u0131nda denklem \u015fu \u015fekilde olur:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kaldirac-Denge-Formulu.jpg\" alt=\"Kald\u0131ra\u00e7 Denge Form\u00fcl\u00fc\" class=\"wp-image-1135\" style=\"width:146px;height:96px\" width=\"146\" height=\"96\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kaldirac-Denge-Formulu.jpg 278w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kaldirac-Denge-Formulu-84x56.jpg 84w\" sizes=\"auto, (max-width: 146px) 100vw, 146px\" \/><\/figure>\n<\/div>\n\n\n<p>Son form\u00fcl\u00fc kullanarak, basit makinenin performans\u0131n\u0131n yan\u0131 s\u0131ra kola g\u00f6re konumunu biliyorsak, belirli bir direncin (y\u00fck bi\u00e7iminde) \u00fcstesinden gelmek i\u00e7in ne kadar kuvvete ihtiyac\u0131m\u0131z oldu\u011funu hesaplamak kolayd\u0131r.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Bir Kald\u0131ra\u00e7 G\u00f6revi<\/h3>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">\u00d6rnek 1: Bir tarafta 10000 N (Newton) y\u00fck\u00fc olan bir kolu, kuvvetin kar\u015f\u0131 taraftan 4 metre uygulanmas\u0131 gerekiyorsa, dayanak noktas\u0131ndan 50 santimetre uzakl\u0131kta dengelemek i\u00e7in ne kadar kuvvet gerekti\u011fini hesaplay\u0131n. dayanak noktas\u0131na g\u00f6re.<\/p>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">Verilen veriler \u015funlard\u0131r:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>a=4m<\/li>\n\n\n\n<li>b=50cm=0,5m (santimetreden metreye gerekli d\u00f6n\u00fc\u015f\u00fcm)<\/li>\n\n\n\n<li>G=10000N<\/li>\n\n\n\n<li>F-?<\/li>\n<\/ul>\n\n\n\n<p class=\"has-vivid-purple-color has-text-color\">Son t\u00fcretilmi\u015f denklemde kar\u015f\u0131l\u0131k gelen de\u011ferleri de\u011fi\u015ftirerek a\u015fa\u011f\u0131daki ifade elde edilir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kaldirac-dengeleme-2.jpg\" alt=\"Kald\u0131ra\u00e7  dengeleme\" class=\"wp-image-1137\" style=\"width:138px;height:91px\" width=\"138\" height=\"91\" srcset=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kaldirac-dengeleme-2.jpg 278w, https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Kaldirac-dengeleme-2-84x56.jpg 84w\" sizes=\"auto, (max-width: 138px) 100vw, 138px\" \/><\/figure>\n<\/div>\n\n\n<p class=\"has-vivid-purple-color has-text-color\">Hesaplamay\u0131 tamamlad\u0131ktan sonra kuvvetin 1250 Newton oldu\u011fu ortaya \u00e7\u0131k\u0131yor.<\/p>\n\n\n\n<p>G\u00f6revdeki hesaplamadan itibaren kald\u0131rac\u0131n faydal\u0131 etkisi a\u00e7\u0131k\u00e7a g\u00f6r\u00fclmektedir. Kullan\u0131m\u0131yla 10000 Newton&#8217;luk bir y\u00fck\u00fcn \u00fcstesinden yaln\u0131zca 1250 Newton&#8217;luk bir kuvvetle gelinebilir (8 kat daha az kuvvet, \u00e7\u00fcnk\u00fc kuvvetin kolu, y\u00fck\u00fcn kolundan 8 kat daha uzundur).<\/p>\n\n\n\n<p>Kald\u0131ra\u00e7ta kuvvet kolunun uzunlu\u011funun da \u00f6nemli oldu\u011funu g\u00f6steren ilgin\u00e7 bir ger\u00e7ek: Ar\u015fimed \u015f\u00f6yle dedi: Bana yeterince uzun bir kald\u0131ra\u00e7 verin, D\u00fcnya gezegenini hareket ettireyim.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-css-opacity\"\/>\n\n\n<form role=\"search\" method=\"get\" action=\"https:\/\/www.matematikazavsicki.com\/tr\/\" class=\"wp-block-search__button-outside wp-block-search__icon-button wp-block-search\"    ><label class=\"wp-block-search__label\" for=\"wp-block-search__input-1\" >Gerekli malzemeyi kolayca bulun! 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Kald\u0131ra\u00e7, daha b\u00fcy\u00fck bir direncin \u00fcstesinden gelebilece\u011fimiz bir kuvveti [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":1129,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[132,133,5,6,14],"tags":[332,330,331,333,47],"class_list":["post-1117","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-10-sinif-matematik","category-11-sinif-matematik","category-8-sinif-matematik","category-9-sinif-matematik","category-fizik","tag-denge","tag-kaldirac","tag-kol","tag-kosulu","tag-turleri"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Kald\u0131ra\u00e7<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Kald\u0131ra\u00e7\" \/>\n<meta property=\"og:description\" content=\"Kald\u0131ra\u00e7, z\u0131t d\u00f6n\u00fc\u015flere neden olan en az iki kuvvetin etkisi alt\u0131nda, bir nokta veya eksen etraf\u0131nda d\u00f6nebilen herhangi bir kat\u0131 cisimdir. Kald\u0131ra\u00e7, daha b\u00fcy\u00fck bir direncin \u00fcstesinden gelebilece\u011fimiz bir kuvveti [&hellip;]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/\" \/>\n<meta property=\"og:site_name\" content=\"Matematik\" \/>\n<meta property=\"article:published_time\" content=\"2023-10-01T22:29:21+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-10-01T22:29:22+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Tek-Tarafli-Kol.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"500\" \/>\n\t<meta property=\"og:image:height\" content=\"339\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Blaze Angelov\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Blaze Angelov\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/\",\"url\":\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/\",\"name\":\"Kald\u0131ra\u00e7\",\"isPartOf\":{\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/#primaryimage\"},\"image\":{\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Tek-Tarafli-Kol.jpg\",\"datePublished\":\"2023-10-01T22:29:21+00:00\",\"dateModified\":\"2023-10-01T22:29:22+00:00\",\"author\":{\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/#\/schema\/person\/c0511828591bd00433a95b3155f1b471\"},\"breadcrumb\":{\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/\"]}]},{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/#primaryimage\",\"url\":\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Tek-Tarafli-Kol.jpg\",\"contentUrl\":\"https:\/\/www.matematikazavsicki.com\/tr\/wp-content\/uploads\/2023\/10\/Tek-Tarafli-Kol.jpg\",\"width\":500,\"height\":339,\"caption\":\"Kald\u0131ra\u00e7\"},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/www.matematikazavsicki.com\/tr\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Kald\u0131ra\u00e7\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/#website\",\"url\":\"https:\/\/www.matematikazavsicki.com\/tr\/\",\"name\":\"Matematik\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/www.matematikazavsicki.com\/tr\/?s={search_term_string}\"},\"query-input\":{\"@type\":\"PropertyValueSpecification\",\"valueRequired\":true,\"valueName\":\"search_term_string\"}}],\"inLanguage\":\"en-US\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/#\/schema\/person\/c0511828591bd00433a95b3155f1b471\",\"name\":\"Blaze Angelov\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/www.matematikazavsicki.com\/tr\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/1a6244e6f81fd50df6172cc11c7bafcdc0c79080dc8fbf4f2f195abd437af8d0?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/1a6244e6f81fd50df6172cc11c7bafcdc0c79080dc8fbf4f2f195abd437af8d0?s=96&d=mm&r=g\",\"caption\":\"Blaze Angelov\"},\"sameAs\":[\"http:\/\/matematikazavsicki.com\/tr\"],\"url\":\"https:\/\/www.matematikazavsicki.com\/tr\/author\/matematik\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Kald\u0131ra\u00e7","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/www.matematikazavsicki.com\/tr\/kaldirac\/","og_locale":"en_US","og_type":"article","og_title":"Kald\u0131ra\u00e7","og_description":"Kald\u0131ra\u00e7, z\u0131t d\u00f6n\u00fc\u015flere neden olan en az iki kuvvetin etkisi alt\u0131nda, bir nokta veya eksen etraf\u0131nda d\u00f6nebilen herhangi bir kat\u0131 cisimdir. 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